#include <ta/taexplicit.hh>
spot::state_ta_explicit::state_ta_explicit |
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const state * |
tgba_state, |
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const bdd |
tgba_condition, |
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bool |
is_initial_state = false , |
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bool |
is_accepting_state = false , |
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bool |
is_livelock_accepting_state = false , |
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transitions * |
trans = 0 |
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inline |
virtual spot::state_ta_explicit::~state_ta_explicit |
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inlinevirtual |
void spot::state_ta_explicit::add_transition |
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transition * |
t, |
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bool |
add_at_beginning = false |
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virtual int spot::state_ta_explicit::compare |
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const spot::state * |
other) | |
const |
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virtual |
Compares two states (that come from the same automaton).
This method returns an integer less than, equal to, or greater than zero if this is found, respectively, to be less than, equal to, or greater than other according to some implicit total order.
This method should not be called to compare states from different automata.
- See Also
- spot::state_ptr_less_than
Implements spot::state.
void spot::state_ta_explicit::delete_stuttering_and_hole_successors |
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Remove stuttering transitions and transitions leading to states having no successors.
virtual void spot::state_ta_explicit::destroy |
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const |
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inlinevirtual |
Release a state.
Methods from the tgba or tgba_succ_iterator always return a new state that you should deallocate with this function. Before Spot 0.7, you had to "delete" your state directly. Starting with Spot 0.7, you should update your code to use this function instead. destroy() usually call delete, except in subclasses that destroy() to allow better memory management (e.g., no memory allocation for explicit automata).
Reimplemented from spot::state.
void spot::state_ta_explicit::free_transitions |
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const bdd spot::state_ta_explicit::get_tgba_condition |
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const |
const state* spot::state_ta_explicit::get_tgba_state |
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const |
transitions* spot::state_ta_explicit::get_transitions |
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const |
transitions* spot::state_ta_explicit::get_transitions |
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bdd |
condition) | |
const |
virtual size_t spot::state_ta_explicit::hash |
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const |
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virtual |
Hash a state.
This method returns an integer that can be used as a hash value for this state.
Note that the hash value is guaranteed to be unique for all equal states (in compare()'s sense) for only has long has one of these states exists. So it's OK to use a spot::state as a key in a hash_map
because the mere use of the state as a key in the hash will ensure the state continues to exist.
However if you create the state, get its hash key, delete the state, recreate the same state, and get its hash key, you may obtain two different hash keys if the same state were not already used elsewhere. In practice this weird situation can occur only when the state is BDD-encoded, because BDD numbers (used to build the hash value) can be reused for other formulas. That probably doesn't matter, since the hash value is meant to be used in a hash_map
, but it had to be noted.
Implements spot::state.
bool spot::state_ta_explicit::is_accepting_state |
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const |
bool spot::state_ta_explicit::is_hole_state |
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const |
Return true if the state has no successors.
bool spot::state_ta_explicit::is_initial_state |
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const |
bool spot::state_ta_explicit::is_livelock_accepting_state |
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const |
void spot::state_ta_explicit::set_accepting_state |
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bool |
is_accepting_state) | |
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void spot::state_ta_explicit::set_initial_state |
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bool |
is_initial_state) | |
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void spot::state_ta_explicit::set_livelock_accepting_state |
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bool |
is_livelock_accepting_state) | |
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bool spot::state_ta_explicit::is_accepting_state_ |
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private |
bool spot::state_ta_explicit::is_initial_state_ |
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private |
bool spot::state_ta_explicit::is_livelock_accepting_state_ |
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private |
const bdd spot::state_ta_explicit::tgba_condition_ |
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private |
const state* spot::state_ta_explicit::tgba_state_ |
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private |
The documentation for this class was generated from the following file: